Solve the inequality 2x + 1 < (3x + 2)/x + 2
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- DongreatModerator
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2x + 1 < (3x + 2)/x + 2
solutio:
we remove bracket
=2x + 1 > 3x + 2/x + 2
collection of like terms
=2x+3x>2+1/x+2
=5x+3/x+2
solutio:
we remove bracket
collection of like terms
=2x+3x>2+1/x+2
=5x+3/x+2
Last edited by Dongreat on Sun 26 Jun 2016, 3:31 pm; edited 1 time in total
- ForumfatherLv3: Senior Member
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2x+1<(3x+2)/x+2
firstly finding the L.C.M
and the L.C.M is x+2
therefore
2x+1(x+2)<3x+2
open the bracket
2x2 + 4x + x + 2 < 3x + 2
collect like terms
=2x2 + 4x + x - 3x < 2-2
=2x2 + 2x < 0
=2(x2 + x) < 0
firstly finding the L.C.M
and the L.C.M is x+2
therefore
2x+1(x+2)<3x+2
open the bracket
2x2 + 4x + x + 2 < 3x + 2
collect like terms
=2x2 + 4x + x - 3x < 2-2
=2x2 + 2x < 0
=2(x2 + x) < 0
- DongreatModerator
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I think I made a mistake
2x+1<(3x+2)/x+2
L.C.M = x+2
:.
2x+1(x+2)<3x+2
2x2 + 4x + x + 2 < 3x + 2
CLT
=2x^2 + 4x + x - 3x < 2-2
=2x^2 + 2x < 0
Then break it down by dividing 2x^2 + 2x by 2 which is
2x^2+2x/2
=x^2+x < 0
=x>-1 Answer
2x+1<(3x+2)/x+2
L.C.M = x+2
:.
2x+1(x+2)<3x+2
2x2 + 4x + x + 2 < 3x + 2
CLT
=2x^2 + 4x + x - 3x < 2-2
=2x^2 + 2x < 0
Then break it down by dividing 2x^2 + 2x by 2 which is
=x^2+x < 0
=x>-1 Answer
Last edited by Dongreat on Mon 27 Jun 2016, 11:08 pm; edited 1 time in total
- ForumfatherLv3: Senior Member
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@Dongreat thanks for noting ur mistakes
- YiraubLv0: Stranger
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very cool
- DongreatModerator
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Forumfather wrote:@Dongreat thanks for noting ur mistakes
Yep and thanks for correcting me. But you should break it down
- VenusgLv3: Senior Member
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Dongreat wrote:Forumfather wrote:@Dongreat thanks for noting ur mistakes
Yep and thanks for correcting me. But you should break it down
- BensonLv3: Senior Member
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@Dongreat u did a nice job
- ParadiseAdministrator
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Benson wrote:@Dongreat u did a nice job
- HatchSuper Moderator
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vry cool
- GoldLv3: Senior Member
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- SpeedLv2: Member
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=2(x2 + x) < 0
- BrainstormLv3: Senior Member
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Answered already
- HatchSuper Moderator
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Brainstorm wrote:Answered already
U can still solve with different formulae
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