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Solve the inequality 2x + 1 < (3x + 2)/x + 2

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Dongreat
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PostDongreat on Sun 26 Jun 2016, 8:29 am

2x + 1 < (3x + 2)/x + 2

solutio:

we remove bracket
=2x + 1 > 3x + 2/x + 2

collection of like terms
=2x+3x>2+1/x+2
=5x+3/x+2


Last edited by Dongreat on Sun 26 Jun 2016, 3:31 pm; edited 1 time in total
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PostForumfather on Sun 26 Jun 2016, 12:41 pm

2x+1<(3x+2)/x+2

firstly finding the L.C.M
and the L.C.M is x+2

therefore
2x+1(x+2)<3x+2

open the bracket
2x2 + 4x + x + 2 < 3x + 2

collect like terms
=2x2 + 4x + x - 3x < 2-2
=2x2 + 2x < 0
=2(x2 + x) < 0
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PostDongreat on Sun 26 Jun 2016, 3:29 pm

I think I made a mistake
2x+1<(3x+2)/x+2
L.C.M = x+2
:.
2x+1(x+2)<3x+2
2x2 + 4x + x + 2 < 3x + 2
CLT
=2x^2 + 4x + x - 3x < 2-2
=2x^2 + 2x < 0



Then break it down by dividing 2x^2 + 2x by 2 which is
2x^2+2x/2

=x^2+x < 0
=x>-1 Answer


Last edited by Dongreat on Mon 27 Jun 2016, 11:08 pm; edited 1 time in total
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PostForumfather on Sun 26 Jun 2016, 3:46 pm

@Dongreat thanks for noting ur mistakes
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PostYiraub on Sun 26 Jun 2016, 5:30 pm

very cool
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Dongreat
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PostDongreat on Sun 26 Jun 2016, 11:45 pm

@Forumfather wrote:@Dongreat thanks for noting ur mistakes

Yep and thanks for correcting me. But you should break it down
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PostVenusg on Thu 22 Sep 2016, 11:10 am

@Dongreat wrote:
@Forumfather wrote:@Dongreat thanks for noting ur mistakes

Yep and thanks for correcting me. But you should break it down
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PostBenson on Tue 08 Nov 2016, 8:11 am

@Dongreat u did a nice job




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PostParadise on Tue 08 Nov 2016, 12:49 pm

@Benson wrote:@Dongreat u did a nice job


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PostHatch on Fri 09 Dec 2016, 5:23 pm

vry cool


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PostGold on Fri 09 Dec 2016, 7:20 pm

smile
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PostSpeed on Fri 09 Dec 2016, 8:24 pm

=2(x2 + x) < 0
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PostBrainstorm on Sat 10 Dec 2016, 5:44 am

Answered already
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PostHatch on Sat 10 Dec 2016, 6:25 am

@Brainstorm wrote:Answered already

U can still solve with different formulae


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